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Code d'Examen: 1D0-541
Nom d'Examen: CIW (CIW v5 Database Design Specialist )
Questions et réponses: 125 Q&As
1D0-541 Démo gratuit à télécharger: http://www.pass4test.fr/1D0-541.html
NO.1 Consider the following four database design activities: 1 - Design user views. 2 - Select a DBMS. 3 -
Apply normalization. 4 - Determine entities. Which choice shows the correct ordering of these activities,
from first to last, by assigned numbers?
A.1, 2, 3, 4
B.3, 4, 1, 2
C.4, 1, 3, 2
D.4, 2, 3, 1
Answer:D
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NO.2 Which process is used to prevent the current database operation from reading or writing a data item
while that data item is being accessed by another operation?
A.Lock
B.Deadlock
C.Timestamp
D.Batch
Answer:A
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NO.3 Which of the following describes two desirable characteristics of a primary key?
A.A primary key should be a value that may be null and may change over time.
B.A primary key should be a value that is not null and will never change.
C.A primary key should consist of meaningful data and a value that can be changed if needed.
D.A primary key should not consist of meaningful data and a value that can be changed if needed.
Answer:B
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NO.4 Which relational algebraic operation is used to select specific columns (attributes) from a relation?
A.Union
B.Difference
C.Projection
D.Intersection
Answer:C
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NO.5 The exhibit shows a table called Student Relation that tracks all information related to a students
courses, professors and sites. What would be the consequence of removing all records for a student with
the ID 1311?
A.Only an update anomaly would occur.
B.An insertion anomaly would occur.
C.A deletion anomaly would occur.
D.An update anomaly and a deletion anomaly would occur.
Answer:C
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NO.6 Consider the Information Engineering diagram in the exhibit showing a conceptual data model of the
relations BUILDING and RESIDENT. What is the next step in refining the data model?
A.Create intermediate entities.
B.Create a logical data model.
C.Resolve many-to-many relationahips.
D.Identify and resolve complex relationships.
Answer:B
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NO.7 Which of the following occurs in a relation when records are added or removed?
A.The number of domains changes.
B.The attributes in the table change.
C.The cardinality of the relation is fixed but the degree varies.
D.The degree of the relation is fixed but the cardinality varies.
Answer:D
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NO.8 Which of the following best describes a composite key?
A.A composite key is a primary key and foreign key that consists of the first two attributes of a relation.
B.A composite key is a primary or foreign key defined by its parent key attributes.
C.A composite key is a foreign key that consists of the same attributes as the primary key from a related
table.
D.A composite key is a primary or foreign key that consists of two or more attributes of a relation.
Answer:D
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NO.9 Which of the following best describes the information contained in the data dictionary (or system
catalog)?
A.Metadata
B.Data model
C.Table data
D.Metafile
Answer:A
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NO.10 Consider the following relation definitions: STUDENT( Student_Number: integer NOT NULL Name:
variable length character string length 20 ) Primary Key Student_Number HOUSING( Housing_ID: integer
NOT NULL Student_Number: integer NOT NULL Building: variable length character string length 25 )
Primary Key Housing_ID Foreign Key Student_Number References STUDENT(Student_Number) ON
DELETE NO ACTION ON UPDATE CASCADE What are the referential constraints for the relations
defined in these relation definitions?
A.There is no relationship between changes in STUDENT(Student_Number) and
HOUSING(Student_Number).
B.When STUDENT(Student_Number) is changed or deleted, this modification or deletion will
automatically be reflected in HOUSING(Student_Number).
C.Modifications to HOUSING(Student_Number) are automatically reflected in changes to
STUDENT(Student_Number), but deletions are not permitted.
D.Modifications to STUDENT(Student_Number) are automatically reflected in changes to
HOUSING(Student_Number). For a deletion to occur from STUDENT(Student_Number), it must first
occur in HOUSING(Student_Number).
Answer:D
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NO.11 Your enterprise is involved in planning a database project. The exhibit shows the result of one phase of
the database design life cycle. Which term best describes the diagram shown in the exhibit?
A.Information Engineering (IE) data model
B.Corporate data model
C.Database requirements model
D.Entity Relation Data (ERD) model
Answer:B
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NO.12 Consider the following relations shown in the exhibit. Which of the following SQL statements would
return the Customers2 relation from the Customers relation?
A.SELECT * FROM Customers WHERE Satisfaction_Rate <= 80 OR Satisfaction_Rate >= 90;
B.SELECT * FROM Customers WHERE Satisfaction_Rate IN (80 AND 90);
C.SELECT * FROM Customers WHERE Satisfaction_Rate >= 80 AND Satisfaction_Rate <= 89;
D.SELECT * FROM Customers WHERE Satisfaction_Rate BETWEEN (80, 90);
Answer:C
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NO.13 What is the highest normal form of the relation(s) shown in the exhibit?
A.Second normal form
B.First normal form
C.Boyce-Codd normal form
D.Third normal form
Answer:A
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NO.14 Consider the Registration relation shown in the exhibit. Which of the following SQL statements would
return all tuples that have course codes beginning with the letter M?
A.SELECT * FROM Registration WHERE Course_Code = M#;
B.SELECT * FROM Registration WHERE Course_Code LIKE M_;
C.SELECT * FROM Registration WHERE Course_Code LIKE M%;
D.SELECT * FROM Registration WHERE Course_Code = M%;
Answer:C
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NO.15 Consider the following SQL statement and the Orders relation shown in the exhibit: What is the output
of this SQL statement? Answer & Explanation Correct Answer C Explanations No more information
available
Answer:
NO.16 Which characteristic is an advantage of a database management system?
A.Data files are owned and maintained by the users.
B.Database administration is simplified.
C.A standard method can be used to access the database.
D.Data is decentralized.
Answer:C
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NO.17 Consider the following relation definition: STUDENT( Student_Number: integer NOT NULL Name:
variable length character string length 20 NOT NULL) Primary Key Student_Number
HOUSING( Housing_ID: integer NOT NULL Student_Number: integer NOT NULL Building: variable
length character string length 25 NOT NULL) Primary Key Housing_ID Foreign Key Student_Number
References STUDENT(Student_Number) ON DELETE NO CHECK ON UPDATE Which integrity
constraint is violated in this relation definition?
A.Entity integrity
B.Domain constraint
C.Referential integrity
D.Enterprise constraint
Answer:C
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NO.18 Consider the Recreation relation in the exhibit. A data operation that changes one of the tuples for
Student_ID 1003 must be performed. It is necessary to change one of the activities from swimming to
tennis. The Student_ID and Activity attributes make up the primary key for the Recreation relation. All
related information must be altered, as well. Which SQL statement or statements would best accomplish
this?
A.UPDATE Recreation SET Activity, Activity_Fee ('Tennis', 100) WHERE Student_ID = 1003;
B.UPDATE TABLE Recreation SET ACTIVITY = 'Tennis', Activity_Fee = 100 WHERE Student_ID = 1003
AND Activity = Swimming;
C.UPDATE Recreation SET Activity = 'Tennis', Activity_Fee = 100 WHERE Student_ID = 1003 AND
Activity = 'Swimming';
D.DELETE Activity FROM Recreation WHERE Student_ID = 1003; INSERT INTO Recreation VALUES
(1003, 'Tennis', 100);
Answer:C
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NO.19 Which pair of relational algebraic operations requires union compatibility?
A.Projection and Cartesian product
B.Selection and projection
C.Intersection and difference
D.Cartesian product and intersection
Answer:C
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NO.20 Consider the entity-relation (ER) diagram shown in the exhibit. When the logical database design phase
is completed, which of the following is a valid DBDL description of the base relations for the ER diagram?
A.STUDENT( Student_Number: integer NOT NULL Name: variable length character string length 20 NOT
NULL) Primary Key Student_Number CLASS( Class_Num: integer NOT NULL Class_Name: integer NOT
NULL) Primary Key Class_Num
B.STUDENT( Student_Number: integer NOT NULL Name: variable length character string length 20 NOT
NULL) Primary Key Student_Number CLASS( Class_Num: integer NOT NULL Class_Name: integer NOT
NULL) Primary Key Class_Num Foreign Key Class_Num References STUDENT
C.STUDENT( Student_Number: integer NOT NULL Name: variable length character string length 20 NOT
NULL) Primary Key Student_Number STU_CLASS( Student_Number: integer NOT NULL Class_Num:
integer NOT NULL) Primary Key Student_Number CLASS( Class_Num: integer NOT NULL Class_Name:
integer NOT NULL) Primary Key Class_Num
D.STUDENT( Student_Number: integer NOT NULL Name: variable length character string length 20 NOT
NULL) Primary Key Student_Number STU_CLASS( Student_Number: integer NOT NULL Class_Num:
integer NOT NULL) Primary Key Student_Number CLASS( Class_Num: integer NOT NULL Class_Name:
integer NOT NULL) Primary Key Class_Num
Answer:D
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